Halliday , Resnick Fundamentals Of Physics (7Th Ed) Solutions 솔루션 다운





Halliday , Resnick Fundamentals Of Physics (7Th Ed) Solutions 솔루션

할리데이 대학물리 7판.

1. Using the given conversion factors, we find (a) the distance d in rods to be d = 4.0 furlongs =

( 4.0 furlongs )( 201.168 m furlong )
5.0292 m rod

= 160 rods,

(b) and that distance in chains to be d =

( 4.0 furlongs )( 201.168 m furlong )
20.117 m chain

= 40 chains.

2. The conversion factors 1 gry = 1/10 line , 1 line=1/12 inch and 1 point = 1/72 inch imply that 1 gry = (1/10)(1/12)(72 points) = 0.60 point. Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .

3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the inside front cover of the textbook (see also Table 1?2). (a) Since 1 km = 1 × 103 m and 1 m = 1 × 106 μm,
1km = 103 m = 103 m 106 μ m m = 109 μ m.

(

)(

)

The given measurement is 1.0 km (two significant figures), which implies our result should be written as 1.0 × 109 μm. (b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10?2 m,
1cm = 10?2 m = 10 ?


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